Integrand size = 19, antiderivative size = 105 \[ \int x^2 \sqrt {a x^2+b x^3} \, dx=\frac {2 \left (a x^2+b x^3\right )^{3/2}}{9 b}-\frac {32 a^3 \left (a x^2+b x^3\right )^{3/2}}{315 b^4 x^3}+\frac {16 a^2 \left (a x^2+b x^3\right )^{3/2}}{105 b^3 x^2}-\frac {4 a \left (a x^2+b x^3\right )^{3/2}}{21 b^2 x} \]
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Time = 0.08 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {2041, 2027, 2039} \[ \int x^2 \sqrt {a x^2+b x^3} \, dx=-\frac {32 a^3 \left (a x^2+b x^3\right )^{3/2}}{315 b^4 x^3}+\frac {16 a^2 \left (a x^2+b x^3\right )^{3/2}}{105 b^3 x^2}-\frac {4 a \left (a x^2+b x^3\right )^{3/2}}{21 b^2 x}+\frac {2 \left (a x^2+b x^3\right )^{3/2}}{9 b} \]
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Rule 2027
Rule 2039
Rule 2041
Rubi steps \begin{align*} \text {integral}& = \frac {2 \left (a x^2+b x^3\right )^{3/2}}{9 b}-\frac {(2 a) \int x \sqrt {a x^2+b x^3} \, dx}{3 b} \\ & = \frac {2 \left (a x^2+b x^3\right )^{3/2}}{9 b}-\frac {4 a \left (a x^2+b x^3\right )^{3/2}}{21 b^2 x}+\frac {\left (8 a^2\right ) \int \sqrt {a x^2+b x^3} \, dx}{21 b^2} \\ & = \frac {2 \left (a x^2+b x^3\right )^{3/2}}{9 b}+\frac {16 a^2 \left (a x^2+b x^3\right )^{3/2}}{105 b^3 x^2}-\frac {4 a \left (a x^2+b x^3\right )^{3/2}}{21 b^2 x}-\frac {\left (16 a^3\right ) \int \frac {\sqrt {a x^2+b x^3}}{x} \, dx}{105 b^3} \\ & = \frac {2 \left (a x^2+b x^3\right )^{3/2}}{9 b}-\frac {32 a^3 \left (a x^2+b x^3\right )^{3/2}}{315 b^4 x^3}+\frac {16 a^2 \left (a x^2+b x^3\right )^{3/2}}{105 b^3 x^2}-\frac {4 a \left (a x^2+b x^3\right )^{3/2}}{21 b^2 x} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.50 \[ \int x^2 \sqrt {a x^2+b x^3} \, dx=\frac {2 \left (x^2 (a+b x)\right )^{3/2} \left (-16 a^3+24 a^2 b x-30 a b^2 x^2+35 b^3 x^3\right )}{315 b^4 x^3} \]
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Time = 2.58 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.30
method | result | size |
pseudoelliptic | \(\frac {2 \left (b x +a \right )^{\frac {3}{2}} \left (15 b^{2} x^{2}-12 a b x +8 a^{2}\right )}{105 b^{3}}\) | \(32\) |
gosper | \(-\frac {2 \left (b x +a \right ) \left (-35 b^{3} x^{3}+30 a \,b^{2} x^{2}-24 a^{2} b x +16 a^{3}\right ) \sqrt {b \,x^{3}+a \,x^{2}}}{315 b^{4} x}\) | \(57\) |
default | \(-\frac {2 \left (b x +a \right ) \left (-35 b^{3} x^{3}+30 a \,b^{2} x^{2}-24 a^{2} b x +16 a^{3}\right ) \sqrt {b \,x^{3}+a \,x^{2}}}{315 b^{4} x}\) | \(57\) |
risch | \(-\frac {2 \sqrt {x^{2} \left (b x +a \right )}\, \left (-35 b^{4} x^{4}-5 a \,b^{3} x^{3}+6 a^{2} b^{2} x^{2}-8 a^{3} b x +16 a^{4}\right )}{315 x \,b^{4}}\) | \(61\) |
trager | \(-\frac {2 \left (-35 b^{4} x^{4}-5 a \,b^{3} x^{3}+6 a^{2} b^{2} x^{2}-8 a^{3} b x +16 a^{4}\right ) \sqrt {b \,x^{3}+a \,x^{2}}}{315 b^{4} x}\) | \(63\) |
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Time = 0.25 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.59 \[ \int x^2 \sqrt {a x^2+b x^3} \, dx=\frac {2 \, {\left (35 \, b^{4} x^{4} + 5 \, a b^{3} x^{3} - 6 \, a^{2} b^{2} x^{2} + 8 \, a^{3} b x - 16 \, a^{4}\right )} \sqrt {b x^{3} + a x^{2}}}{315 \, b^{4} x} \]
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\[ \int x^2 \sqrt {a x^2+b x^3} \, dx=\int x^{2} \sqrt {x^{2} \left (a + b x\right )}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.50 \[ \int x^2 \sqrt {a x^2+b x^3} \, dx=\frac {2 \, {\left (35 \, b^{4} x^{4} + 5 \, a b^{3} x^{3} - 6 \, a^{2} b^{2} x^{2} + 8 \, a^{3} b x - 16 \, a^{4}\right )} \sqrt {b x + a}}{315 \, b^{4}} \]
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Time = 0.26 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.25 \[ \int x^2 \sqrt {a x^2+b x^3} \, dx=\frac {32 \, a^{\frac {9}{2}} \mathrm {sgn}\left (x\right )}{315 \, b^{4}} + \frac {2 \, {\left (\frac {9 \, {\left (5 \, {\left (b x + a\right )}^{\frac {7}{2}} - 21 \, {\left (b x + a\right )}^{\frac {5}{2}} a + 35 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{2} - 35 \, \sqrt {b x + a} a^{3}\right )} a \mathrm {sgn}\left (x\right )}{b^{3}} + \frac {{\left (35 \, {\left (b x + a\right )}^{\frac {9}{2}} - 180 \, {\left (b x + a\right )}^{\frac {7}{2}} a + 378 \, {\left (b x + a\right )}^{\frac {5}{2}} a^{2} - 420 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{3} + 315 \, \sqrt {b x + a} a^{4}\right )} \mathrm {sgn}\left (x\right )}{b^{3}}\right )}}{315 \, b} \]
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Time = 9.02 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.59 \[ \int x^2 \sqrt {a x^2+b x^3} \, dx=\frac {2\,\sqrt {b\,x^3+a\,x^2}\,\left (-16\,a^4+8\,a^3\,b\,x-6\,a^2\,b^2\,x^2+5\,a\,b^3\,x^3+35\,b^4\,x^4\right )}{315\,b^4\,x} \]
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